# Popravka Ves Masine.pdf [WORK]

Popravka Ves Masine.pdf [WORK] Popravka Ves Masine.pdf

The larger value is the length of the arm of the dog at the starting position. There is a corresponding value for the pant leg length. This illustrates the position of the body in relation to the cloth.

Since the force is perpendicular to the cloth surface, one can estimate the force by multiplying the cloth acceleration with the cloth mass:

$$F=ma$$

where

$$m=\frac{1}{2}C\rho\,R^2 =\frac{1}{2} \rho\,v^2$$

Here, $v$ denotes the linear velocity. The cloth mass can be calculated in kg.
Thus, the force would be:
$$F=\frac{1}{2} \rho\,v^2 =\frac{1}{2}\rho\,R^2 \frac{v^2}{R}$$

or in W/m²
$$F=\frac{1}{2} m \omega^2$$

with the angular velocity $\omega$ in rad/s.
If you want the force to be divided by $R$ and the pressure $p$ to be divided by the cloth surface $C$, then the force becomes
$$F =\frac{1}{2}\rho R^3 \frac{v^2}{C}$$
or $$F = \frac{1}{2} \rho R^3 \frac{v^2}{gC}$$
if a gravitational acceleration $g$ is considered. This results in the pressure $p$ being
$$p = F/ C = \frac{1}{2} \rho R^3 \frac{v^2}{gC}$$

or
$$p = \frac{1}{2} \rho R^3 \frac{v^2}{gC} / (\pi R^2)$$

The influence of gravity becomes very important if the cloth mass is very large. Since that could be the case for a shirt or a dress.
If the cloth mass is that small, or in other words, if gravity does not play a role, then the force is
$$F = \frac{1}{2} m a^2$$

If the force is perpendicular to the cloth surface, then the cloth acceleration will be zero and the linear velocity will be the constant angular

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